4x^2-24x-99=0

Solution for 4x^2-24x-99=0 equation:

4x^2-24x-99=0

a = 4; b = -24; c = -99;
Δ = b2-4ac
Δ = -242-4·4·(-99)
Δ = 2160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2160}=\sqrt{144*15}=\sqrt{144}*\sqrt{15}=12\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-12\sqrt{15}}{2*4}=\frac{24-12\sqrt{15}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+12\sqrt{15}}{2*4}=\frac{24+12\sqrt{15}}{8}
$